4^x+4^x^+^1+4^x^+^2=336

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Solution for 4^x+4^x^+^1+4^x^+^2=336 equation: 



4^x+4^x^+^1+4^x^+^2=336

We move all terms to the left:

4^x+4^x^+^1+4^x^+^2-(336)=0

determiningTheFunctionDomain
4^x+4^x^+4^x^-336+^1+^2=0

We add all the numbers together, and all the variables

4^x+4^x^+4^x^=0

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